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In C++, why does auto not work with std::atomic?
General recommendation online seems to be to use auto where possible.But this doesn't work:auto cnt = std::atomic<int>{0};While this works fine:std::atomic<int> cnt {0};Is there a...
View ArticleAnswer by Justin for In C++, why does auto not work with std::atomic?
std::atomic is immovable because it has a deleted copy constructor. Prior to C++17, auto cnt = std::atomic<int>{0}; tries to call the move constructor to move the temporary into cnt, so you can't...
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